A、0.18m<sub>0sub>c2 B、0.25m<sub>0sub>c2 C、0.36m<sub>0sub>c2 D、1.25m<sub>0sub>c2
A、若把电子想象为一个相对介电常数mg src="https://img.ppkao.com/2019-05/wuacheng/2019050716243326649.jpg" />的球体,它的电荷-e在球体内均匀分布。假设电子的静电能量等于它的静止能量m<sub>0sub>c2时(m<sub>0sub>为电子的静止质量,c为真空中的光速),求电子半径R。
A、M<sub>0sub>为试件烘干前质量,单位为g B、M<sub>0sub>为试件烘干后质量,单位为g C、r<sub>0sub>为干密度,单位为kg/m3 D、r<sub>0sub>为干密度,单位为g/m3
A、M<sub>1sub>=M<sub>2sub>=M<sub>0sub> B、M<sub>1sub>=M<sub>2sub>=2M<sub>0sub> C、M<sub>1sub>=M<sub>2sub>=1/2M<sub>0sub> D、M<sub>1sub>+M<sub>2sub>=2M<sub>0sub>
A、W<sub>Esub>=1,M<sub>Esub>=0 B、W<sub>Esub>=1,M<sub>Esub>=1 C、W<sub>Esub>=0,M<sub>Esub>=0 D、W<sub>Esub>=0,M<sub>Esub>=1
A、Δ<sub>rsub>Hθ<sub>msub>〉0,Δ<sub>rsub>Sθ<sub>msub>〉0 B、Δ<sub>rsub>Hθ<sub>msub>〉0,Δ<sub>rsub>Sθ<sub>msub>〈0 C、Δ<sub>rsub>Hθ<sub>msub>〈0,Δ<sub>rsub>Sθ<sub>msub>〈0 D、Δ<sub>rsub>Hθ<sub>msub>〈0,Δ<sub>rsub>Sθ<sub>msub>〉0
A、如图所示,质量为m=1×10-6kg、电荷量为q=1c的带电粒子(不计重力),以初速度v<sub>0sub>=2×106m/s垂直进入磁感应强度为B=1T、宽度为L=1m的匀强磁场区域,并从磁场右侧飞出。求
mg src="https://img.ppkao.com/2019-05/yuanhuijuan/2019050816493732653.jpg" />
A、Δ<sub>rsub>G<sub>msub>(1)0=2Δ<sub>rsub>G<sub>msub>(2)0,K<sub>1sub>0=K<sub>2sub>0 B、Δ<sub>rsub>G<sub>msub>(1)0=2Δ<sub>rsub>G<sub>msub>(2)0,K<sub>1sub>0=(K<sub>2sub>0)2 C、Δ<sub>rsub>G<sub>msub>(1)0=Δ<sub>rsub>G<sub>msub>(2)0,K<sub>1sub>0=(K<sub>2sub>0)2 D、Δ<sub>rsub>G<sub>msub>(1)0=Δ<sub>rsub>G<sub>msub>(2)0,K<sub>1sub>0=K<sub>2sub>0
A、M<sub>Asub>/M<sub>Bsub> B、M<sub>Bsub>/M<sub>Asub> C、C<sub>Bsub>/C<sub>Asub> D、C<sub>Asub>/C<sub>Bsub>