A、K<sub>1sub>+K<sub>2sub> B、K<sub>1sub>-K<sub>2sub> C、K<sub>1sub>·K<sub>2sub> D、K<sub>1sub>/K<sub>2sub>
A、K<sub>1sub>+K<sub>2sub> B、K<sub>1sub>-K<sub>2sub> C、K<sub>1sub>·K<sub>2sub> D、K<sub>1sub>/K<sub>2sub>
A、k<sub>0sub>=k<sub>ssub> B、k<sub>0sub><k<sub>ssub> C、k<sub>0sub>>k<sub>ssub> D、反应系统不稳定,无法测得k<sub>ssub>
A、K<sub>1sub>+K<sub>2sub> B、K<sub>1sub>-K<sub>2sub> C、K<sub>1sub>·K<sub>2sub> D、K<sub>1sub>/K<sub>2sub>
A、有一岩样长3.268cm,截面积4.758cm<sup>2sup>,绝对渗透率为0.1925μm<sup>2sup>,若岩样两端施加压差,测得不同含水饱和度下油相相对渗透率和水相相对渗透率实验数据如表,并已知油的粘度为7.6mPa.s,水的粘度为0.31mPa.s,若岩样两端施加压差5atm,试求: 
(1)S<sub>wsub>=60.21%时油相相对渗透率K<sub>rosub>,油相有效渗透率K<sub>osub>和水相相对渗透率K<sub>rwsub>和水相有效渗透率K<sub>wsub>;
(2)S<sub>wsub>=60.21%时油的流量、水的流量; 
(3)S<sub>wsub>=60.21%时的油的流度λo、水的流度λw,流度比M。
src="https://img.ppkao.com/2019-04/leiyawen/2019041410171038677.jpg" />
A、K<sup>Øsup><sub>1sub>/ K<sup>Øsup><sub>2sub> B、K<sup>Øsup><sub>2sub>/K<sup>Øsup><sub>1sub> C、K<sup>Øsup><sub>1sub>· K<sup>Øsup><sub>2sub> D、K<sup>Øsup><sub>1sub>- K<sup>Øsup><sub>2sub>
A、ΔS<sub>体sub>+ΔS<sub>环sub>>0 B、ΔS<sub>体sub>+ΔS<sub>环sub><0 C、ΔS<sub>体sub>+ΔS<sub>环sub>=0 D、无法确定
A、A<sub>1sub>-A<sub>2sub> B、(A<sub>1sub>-A<sub>2sub>)K<sub>ssub> C、(A<sub>1sub>-A<sub>2sub>)/K′<sub>ssub> D、(A<sub>1sub>-A<sub>2sub>)K<sub>ssub>/K′<sub>ssub>