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Which three approaches can be used while migrating from an IPV4 addressing scheme to an IPV6 scheme.()

A、statically map IPV4 address to IPV6 addresses

B、configuration IPv4 tunnels between IPV6 islands

C、use DHCPv6 to map IPV4 addresses to IPV6 addresses

D、use proxying and translation to translate IPV6 packets into IPV4 packets

E、configure IPV6 directly

F、enable dual-stack routing

更多“Which three approaches can be used while migrating from an IPV4 addressing scheme to an IPV6 scheme.()”相关的问题
第1题

A、UDP provides delivery notification and error checking mechanisms.  B、UDP is faster than the Transmission Control Protocol (TCP).  C、UDP application examples include DNS and VoIP.  D、UDP is an application layer protocol.  E、UDP uses a best effort delivery approach.  

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第2题

A、This approach does rot support verticalization although It is aligned to partner programs.  B、This approach integrates solutions by combining technologies that are aligned to customer buying patterns.  C、This approach is not aligned to partner programs although it supports verticalization.  D、This approach separates technologies on the basiss of customer buying patterns.  

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第3题

A、A.TCP is a transport layer protocol.  B、B.TCP is faster than the User Datagram Protocol (UDP).  C、C.TCP provides delivery notification and error checking mechanisms.  D、D.TCP uses a best effort delivery approach.  E、E.TCP application examples include HTTP and SMTP.  

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第4题

A、The three moving vanes and the three fixed vanes form three pressure chambers  B、The three moving vanes and the three fixed vanes form six pressure chambers  C、The three moving vanes and the three fixed vanes form nine pressure chambers  D、The three moving vanes and the three fixed vanes form twelve pressure chambers  

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第5题

A、one blast,4 to 6 seconds in duration  B、three blasts,4 to 6 seconds in duration  C、one continuous blast until you are able to see around the bend  D、one blast,8 to 10 seconds in duration  

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第7题

A、Send  B、Raise  C、Delete  D、Receive  E、Acknowledge  

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第8题

A、A.p0 = p1;  B、B.p1 = p2;  C、C.p2 = p4;  D、D.p2 = (ClassC)p1;  E、E.p1 = (ClassB)p3;  F、F.p2 = (ClassC)p4;  

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第10题

A、protocol  B、source-address  C、port  D、application  E、attacks  

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