A、保持完整钝化膜
B、被破坏的钝化膜得到修复
C、不发生腐蚀过程
D、发生电化学腐蚀
更多“原料CO<sub>2</sub>中加入空气，可以使尿素一甲铵液中保持一定浓度的氧，它可以使不锈钢和钛表面（）。”相关的问题
A、C+O<sub>2sub>→CO<sub>2sub>+Q，C+O<sub>2sub>→CO+Q B、CO<sub>2sub>+C→CO-Q，CO+H<sub>2sub>→CH<sub>4sub>+H<sub>2sub>O+Q. C、C+O<sub>2sub>→CO+Q，C+H<sub>2sub>O→CO+H<sub>2sub>-Q D、CO<sub>2sub>+C→CO-Q，C+H<sub>2sub>O→CO+H<sub>2sub>-Q
A、NaCl、NH<sub>3sub>、CO<sub>2sub> B、NaCl、石灰石 C、NaOH、CO<sub>2sub> D、NH<sub>3sub>、CO<sub>2sub>
A、CO、CO<sub>2sub>、O<sub>2sub> B、CO<sub>2sub>、O<sub>2sub>、CO C、O<sub>2sub>、CO、CO<sub>2sub> D、O<sub>2sub>、CO<sub>2sub>、CO
A、C+O<sub>2sub>=CO<sub>2sub> B、CO<sub>2sub>+C=2CO<sub>2sub> C、2CO<sub>2sub>+O<sub>2sub>=2CO<sub>2sub> D、2CO=CO<sub>2sub>+C
A、CO+2H<sub>2sub> = CH<sub>3sub>OH+Q；CO<sub>2sub>+3H<sub>2sub>= CH<sub>3sub>OH+H<sub>2sub>O+Q B、CO+H<sub>2sub>O = CO<sub>2sub>+H<sub>2sub>；4CO+8H<sub>2sub> = C<sub>4sub>H<sub>9sub>OH+3H<sub>2sub>O C、CO+3H<sub>2sub> = CH<sub>4sub>+H<sub>2sub>O+Q ；CO<sub>2sub>+4H<sub>2sub> = CH<sub>4sub>+2H<sub>2sub>O+Q D、CO+2H<sub>2sub> = CH<sub>4sub>+Q；CO<sub>2sub>+3H<sub>2sub> = CH<sub>4sub>+H<sub>2sub>O+Q
A、CO<sub>2sub>＋H<sub>2sub>S→CS<sub>2sub>＋2H<sub>2sub>O B、CO<sub>2sub>＋2S→CS<sub>2sub>＋O<sub>2sub> C、CO<sub>2sub>＋2H<sub>2sub>S→CS<sub>2sub>＋H<sub>2sub>O D、CO<sub>2sub>＋2H<sub>2sub>S→CS<sub>2sub>＋2H<sub>2sub>O
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