A、Z<sub>2sub>Z<sub>3sub>/(Z<sub>2sub>+Z<sub>3sub>) B、Z<sub>1sub>+Z<sub>2sub>Z<sub>3sub>/(Z<sub>2sub>+Z<sub>3sub>) C、Z<sub>1sub>+Z<sub>2sub>+Z<sub>3sub> D、Z<sub>1sub>+(Z<sub>2sub>+Z3)/(Z<sub>2sub>Z<sub>3sub>)
A、Z<sub>2sub>Z<sub>3sub>/(Z<sub>2sub>+Z<sub>3sub>) B、Z<sub>1sub>+Z<sub>2sub>Z<sub>3sub>/(Z<sub>2sub>+Z<sub>3sub>) C、Z<sub>1sub>+Z<sub>2sub>+Z<sub>3sub> D、Z<sub>1sub>+(Z<sub>2sub>+Z3)/(Z<sub>2sub>Z<sub>3sub>)
A、Z<sub>1sub> B、Z<sub>2sub> C、Z<sub>1sub>+Z<sub>2sub> D、Z<sub>1sub>+Z<sub>2sub>+h<sub>wsub>
A、Ez=E<sub>0sub>/(1+z/Rp) B、Ez=E<sub>0sub>/(1-z/R<sub>50sub>) C、Ez=E<sub>0sub>/(1+z/R<sub>50sub>) D、Ez=E<sub>0sub>(1+z/R<sub>50sub>) E、Ez=E<sub>0sub>(1-z/Rp)
A、i=n<sub>主sub>/n<sub>从sub>=z<sub>主sub>/z<sub>从sub> B、i=n<sub>马达sub>/n<sub>从sub>=z<sub>主sub>/z<sub>从sub> C、i=n<sub>主sub>/n<sub>从sub>=z<sub>从sub>/z<sub>主sub> D、i=n<sub>从sub>/n<sub>主sub>=z<sub>从sub>/z<sub>主sub>
A、图示所示轮系,已知Z<sub>1sub>=18、Z<sub>2sub>=20、Z<sub>2’sub>=25、Z<sub>3sub>=25、Z<sub>3’sub>=2、Z<sub>4sub>=40,求该轮系的传动比,并判断蜗轮4的转向。
A、在图示轮系中,各轮齿数为z<sub>1sub>=10,z<sub>2sub>=40,z<sub>2’sub>=15,z<sub>3sub>=30,z<sub>3’sub>=20,z<sub>4sub>=40。试求传动比i<sub>14sub>,并确定O<sub>1sub>和轴O<sub>4sub>的转向是相同还是相反?
A、n<sub>0sub>/z<sub>0sub>=n/z B、n/n<sub>0sub>=z/z<sub>0sub> C、n/z<sub>0sub>=z/n<sub>0sub> D、n<sub>0sub>/n=z/z<sub>0sub>
A、制动力F<sub>bsub>与垂直Z载荷正比F<sub>bsub>/Z B、附着力F<sub>4sub>与垂直Z载荷之比F<sub>4sub>/Z C、转向力F<sub>gsub>与垂直载荷Z证比F<sub>gsub>/Z D、驱动力F<sub>tsub>与垂直载荷Z载之比F<sub>tsub>/Z