A、Z<sub>2sub>Z<sub>3sub>/(Z<sub>2sub>+Z<sub>3sub>) B、Z<sub>1sub>+Z<sub>2sub>Z<sub>3sub>/(Z<sub>2sub>+Z<sub>3sub>) C、Z<sub>1sub>+Z<sub>2sub>+Z<sub>3sub> D、Z<sub>1sub>+(Z<sub>2sub>+Z3)/(Z<sub>2sub>Z<sub>3sub>)
A、Z<sub>2sub>Z<sub>3sub>/(Z<sub>2sub>+Z<sub>3sub>) B、Z<sub>1sub>+Z<sub>2sub>Z<sub>3sub>/(Z<sub>2sub>+Z<sub>3sub>) C、Z<sub>1sub>+Z<sub>2sub>+Z<sub>3sub> D、Z<sub>1sub>+(Z<sub>2sub>+Z3)/(Z<sub>2sub>Z<sub>3sub>)
A、F<sub>1sub>=6N,F<sub>2sub>=0 B、F<sub>1sub>=0,F<sub>2sub>=6N C、F<sub>1sub>=F<sub>2sub>=8N D、F<sub>1sub>=6N,F<sub>2sub>=8N
A、α—Al<sub>2sub>O<sub>3sub> B、β—Al<sub>2sub>O<sub>3sub> C、θ—Al<sub>2sub>O<sub>3sub> D、γ—Al<sub>2sub>O<sub>3sub>
A、I<sub>1sub>-I<sub>2sub>+I<sub>3sub>=5A B、I<sub>1sub>-I<sub>2sub>+I<sub>3sub>=-5A C、-I<sub>1sub>+I<sub>2sub>-I<sub>3sub>=0 D、I<sub>1sub>+I<sub>2sub>+I<sub>3sub>=0
A、U<sub>bsub>+U<sub>1sub>-U<sub>2sub>=0 B、U<sub>bsub>-U<sub>2sub>+U<sub>1sub>=0 C、U<sub>bsub>+U<sub>1sub>+U<sub>2sub>=0 D、U<sub>bsub>-U<sub>1sub>-U<sub>2sub>=0
A、B<sub>0sub>、C<sub>2sub>、B<sub>3sub> B、C<sub>0sub>、F<sub>0sub>、C<sub>1sub>、C<sub>2sub>、B<sub>2sub> C、C<sub>0sub>、F<sub>0sub>、C<sub>2sub>、B<sub>3sub> D、C<sub>0sub>、F<sub>0sub>、C<sub>1sub>、F<sub>2sub>
A、D<sub>1sub>截止,D<sub>2sub>导通 B、D<sub>1sub>导通,D<sub>2sub>截止 C、D<sub>1sub>导通,D<sub>2sub>导通 D、D<sub>1sub>截止,D<sub>2sub>截止
A、下图所示轮系中:z<sub>1sub>=2,z<sub>2sub>=60,z<sub>3sub>=25,z<sub>4sub>=50,z<sub>5sub>=20,z<sub>6sub>=30,又知蜗杆的转速n<sub>1sub>=900rmin,方向如图所示。求若轴B转速n<sub>Bsub>=0,那么轮6的转速n<sub>6sub>?转向如何?以及若n<sub>Bsub>=6r/min,转向如图,那么n<sub>6sub>=?转向如何?
A、试根据下图所示的油水体系的相对渗透率曲线,标注S<sub>1sub>.S<sub>2sub>S<sub>3sub>.K<sub>r1sub>.K<sub>r2sub>各点的名称以及A.B.C各区的名称。