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【单选题】

设a<sub>1</sub>和b<sub>1</sub>都大于0,a<sub>n</sub>=(a<sub>n-1</sub>+b<sub>n-1</sub>)/2,b<sub>n</sub>=2a<sub>n-1</sub>b<sub>n-1</sub>/(2a<sub>n-1</sub>+b<sub>n-1</sub>),则a<sub>n</sub>和b<sub>n</sub>的极限分别为()(sqrt和inf分别表示根号和无穷)

A、sqrt(a1b1),inf

B、sqrt(a2b2),inf

C、sqrt(a1b1),sqrt(a1b1

D、1,1

更多“设a<sub>1</sub>和b<sub>1</sub>都大于0,a<sub>n</sub>=(a<sub>n-1</sub>+b<sub>n-1</sub>)/2,b<sub>n</sub>=2a<sub>n-1</sub>b<sub>n-1</sub>/(2a<sub>n-1</sub>+b<sub>n-1</sub>),则a<sub>n</sub>和b<sub>n</sub>的极限分别为()(sqrt和inf分别表示根号和无穷)”相关的问题
第1题

A、r<sub>1sub>=r<sub>2sub>=0,L<sub>1sub>=L<sub>2sub>=M=0&nbsp;&nbsp;B、r<sub>1sub>=r<sub>2sub>=0,L<sub>1sub>=L<sub>2sub>=M=∞&nbsp;&nbsp;C、r<sub>1sub>=r<sub>2sub>=∞,L<sub>1sub>=L<sub>2sub>=M=0&nbsp;&nbsp;D、r<sub>1sub>=r<sub>2sub>=∞,L<sub>1sub>=L<sub>2sub>=M=∞&nbsp;&nbsp;

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第2题

A、μ<sub>1sub>〈μ<sub>2sub>&nbsp;&nbsp;B、μ<sub>1sub>〉μ<sub>2sub>&nbsp;&nbsp;C、&sigma;<sub>1sub>〈&sigma;<sub>2sub>&nbsp;&nbsp;D、&sigma;<sub>1sub>〉&sigma;<sub>2sub>&nbsp;&nbsp;

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第3题

A、R<sub>Asub>:R<sub>Bsub>=2,T<sub>Asub>:T<sub>Bsub>=2&nbsp;&nbsp;B、R<sub>Asub>:R<sub>Bsub>=1/2,T<sub>Asub>:T<sub>Bsub>=1&nbsp;&nbsp;C、R<sub>Asub>:R<sub>Bsub>=1,T<sub>Asub>:T<sub>Bsub>=1/2&nbsp;&nbsp;D、R<sub>Asub>:R<sub>Bsub>=2,T<sub>Asub>:T<sub>Bsub>=1&nbsp;&nbsp;

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第4题

A、M<sub>1sub>=M<sub>2sub>=M<sub>0sub>&nbsp;&nbsp;B、M<sub>1sub>=M<sub>2sub>=2M<sub>0sub>&nbsp;&nbsp;C、M<sub>1sub>=M<sub>2sub>=1/2M<sub>0sub>&nbsp;&nbsp;D、M<sub>1sub>+M<sub>2sub>=2M<sub>0sub>&nbsp;&nbsp;

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第5题

A、&alpha;<sub>1sub>=&alpha;<sub>2sub>&nbsp;&nbsp;B、&alpha;<sub>2sub>>&alpha;<sub>2sub>&nbsp;&nbsp;C、&alpha;<sub>1sub><&alpha;<sub>2sub>&nbsp;&nbsp;D、与&alpha;<sub>1sub>&alpha;<sub>2sub>无关&nbsp;&nbsp;

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第6题

A、VT<sub>1sub>导通,TV<sub>2sub>截止&nbsp;&nbsp;B、VT<sub>1sub>截止,VT<sub>2sub>导通&nbsp;&nbsp;C、VT<sub>1sub>导通,VT<sub>2sub>导通&nbsp;&nbsp;D、VT<sub>1sub>截止,VT<sub>2sub>截止&nbsp;&nbsp;

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第8题

A、根据图所示的逻辑图及相应的CP、R<sub>Dsub>D的波形,试画出Q<sub>1sub>端Q<sub>2sub>端的输出波形,初始状态Q<sub>1sub>=Q<sub>2sub>=0。&nbsp;&nbsp;

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第9题

A、S<sub>0sub>>S<sub>1sub>>S<sub>2sub>>S<sub>3sub>&nbsp;&nbsp;B、S<sub>0sub>>S<sub>2sub>>S<sub>1sub>>S<sub>3sub>&nbsp;&nbsp;C、S<sub>0sub>>S<sub>1sub>=S<sub>2sub>>S<sub>3sub>&nbsp;&nbsp;D、S<sub>0sub>>S<sub>2sub>>S<sub>3sub>>S<sub>1sub>&nbsp;&nbsp;

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